Pizzaro,
If you wanna speak statisticially, then here we go:
Chosing 102800 out of 13000000 => 0.790769230769231%
Chosing 102800 out of 13000001 => 0.790769169940833%
The difference is => 0.0000000608283976522017%
In other words, that would affect one person every 1643968999 (and not "8 people every 10.000"). Since we have only 13 million applicants, that means reapplying would kill the chance of 0.791% of a person, and not 0.791% of the applicants as you said.
If you do your math correctly, you will find that it affects:
1 person every 1643968999 applicants.
The influence on the probablity is not the question, otherwise no one would apply.
However, I was looking for the legal side. Actually, it is a matter of fact that 55000 selected applicants will not be granted a visa, do not you agree?
Excuse me, you are not doing the same calculation that USAHolic has talked about:
I remind what he said:
USAHolic said:
I don't think 102,800 2010 Dv winners affect the chance of probably 13,000,000 others!
So, If 102,800 winners applicate again over 13,000,000 that would mean (those 102,800 are part of those 13,000,000):
102,800/13,000,000=0,007907692, which is: 0.79%, let's say 0.8%
(in fact yes, I was mistaken, is 0.79% no 0.00079%, ...even worst)
That means, that the 0.8% of the DV-2011 applicants already have a NL.
That means, that when the computer randomly chooses again 102,800 winners, 0.8% of them will have already a previous NL.
What you are saying is if those 102,800 are apart of the 13,000,000 , but what USAHolic's message is saying, at least as I understand it, if in the case that after the DV-2011 process is done, 102,800 would have been the winners, out of 13,000,000 applicants (102,800 of them already winners for the DV-2010).
If you have in a bag 9 white eggs, and you put in 1 brown one, and you enter you hand randomly to get an egg, what would be the chance to get the brown one: 1/10, right? 10%
OK, so if you just put 8 white eggs, and put into the bag 2 brown eggs, what would be now the chance?: 2/10 right 20% (it is higher now).
This is when keeping the population fixed (10 eggs), if not:
- You put 9 white eggs, plus 1 brown one, chance 1/10=10%
- You put 9 white eggs, plus 5 brown one, chance 5/14=35%
The higher is the brown eggs population, the higher is the chance to get one, even not keeping the main population fixed.
The same with winner applicants (brown eggs).
Thanks.
I